How do I populate randomly generated array?

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Trent123
- Joined 30 May, 2015
- 10 topics • 32 posts
1

5 Jan, 2016
Quote

Could someone please assist, either with guidance or a code sample?

If I generate an array with the code

Set size to (random(4,11), random(4,11),1)[/code:3fo36ddv]

how can I ensure that, regardless of array size, the array is always populated as follows:

[img="http://s17.postimg.org/9yjw9oz3z/array.jpg"]

with the "1"'s around the edges, and the "0"'s filling the rest ?

- LittleStain
- - Joined 26 Apr, 2011
  - 23 topics • 6,122 posts
- 1
- 5 Jan, 2016
- Quote
I guess what you'd do is first set a (local) variable to the random number (you should use floor(random(4,12), because you don't want floating numbers..

You could then use those variables to get the last lines in the x and y direction (the first is ofcourse always 0)
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- korbaach
- - Joined 9 Sep, 2014
  - 8 topics • 1,508 posts
- 1
- 11 Jan, 2016
- Quote
how can I ensure that, regardless of array size, the array is always populated as follows:

with the "1"'s around the edges, and the "0"'s filling the rest ?

If I understand correctly...

Array For each XY element

....System:Compare two values
Array.CurX=0|Array.CurY=0|Array.CurX=Array.Width-1|Array.CurY=Array.Height-1 =1[/code:yaw5a9i8] Action.....Array set value at XY ...[b]X[/b](Array.CurX);[b]Y[/b](Array.CurY);[b]Value[/b](1)