# How do I roulette with determined result

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### » Mon Dec 05, 2016 7:23 pm

this is very useful, thanks for sharing.
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### » Mon Dec 05, 2016 7:35 pm

Very nice. Thanks a lot.

In my case, I need that the spinner stops in pre defined places, following a sequence that could be different each time: 1,3,5,4,6,2,6,6,3,1 or 4,2,5,4,1,6,3,1,3,2 or 6,1,4,2,3,5,2,2,4,1 or ...

Is it possible?
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### » Mon Dec 05, 2016 9:03 pm

@Braus
Sure, why not? In the capx it calculates the initial speed so it rotates n degrees. It's done when the speed is >= to 0.

So you'd either figure out the number of degrees from any position to any other, or find a formula that can do that.
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### » Tue Dec 06, 2016 12:47 pm

R0J0hound wrote:@Braus
Sure, why not? In the capx it calculates the initial speed so it rotates n degrees. It's done when the speed is >= to 0.

So you'd either figure out the number of degrees from any position to any other, or find a formula that can do that.

I got it. I just need to fix an issue with the area corresponding to the place 1 (all the restante are okay). How to check if the spinner is over this place if the first angle of this area starts at 330 degrees and finish at 30 degrees. I tried "within 60 of 30" but it nor worked.

Other question:
If I use sqrt(2*50*(360+int(random(6))*60)) I cannot apply more speed at the beginning?
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### » Tue Dec 06, 2016 3:49 pm

"within 60 of 30" would mean 330 to 90, or 60 degrees in each direction from 30. So it probably is easier for you to just use the "is between angles" condition instead.

I don't understand your last question. The equation is:
speed = sqrt(2*deceleration*degreesToMove)

It calculates the speed needed so when using a certain deceleration it will stop after rotating degreesToMove degrees. The speed will be higher for higher values of deceleration and degreesToMove.
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### » Tue Dec 06, 2016 6:14 pm

R0J0hound wrote:"within 60 of 30" would mean 330 to 90, or 60 degrees in each direction from 30. So it probably is easier for you to just use the "is between angles" condition instead.

I don't understand your last question. The equation is:
speed = sqrt(2*deceleration*degreesToMove)

It calculates the speed needed so when using a certain deceleration it will stop after rotating degreesToMove degrees. The speed will be higher for higher values of deceleration and degreesToMove.

I would like that the spinner starts fast (750) but just turn 5 or 7 times and stop in the angle that I defined. Is it possible?
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### » Tue Dec 06, 2016 6:35 pm

A full rotation is 360 so you could just add 360 to degreesToMove multiple times.
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### » Tue Dec 06, 2016 6:51 pm

R0J0hound wrote:A full rotation is 360 so you could just add 360 to degreesToMove multiple times.

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